8-to- 1 multiplexer.

Thread Starter


Joined Sep 25, 2004
Can anybody help me to solve this...............??????

A one-bit full adder is to be implemented using 8-to-1 multiplexers

( a ) Write the t ruth table for sum (S) and carry to the next stage CN in terms of
the two bit ( A, B ) and carry from the previous stage (CP) . The t ruth table
should be in the ascending order of (A,B,CP).

( b ) Implement S and CN using 8-to- 1 multiplexer.

Thanks & best regards,
Ramesh Raju