8-to- 1 multiplexer.

Discussion in 'Homework Help' started by ramesh_ime, Sep 26, 2004.

  1. ramesh_ime

    Thread Starter New Member

    Sep 25, 2004
    Can anybody help me to solve this...............??????

    A one-bit full adder is to be implemented using 8-to-1 multiplexers

    (a) Write the t ruth table for sum (S) and carry to the next stage CN in terms of
    the two bit (A, B) and carry from the previous stage (CP) . The t ruth table
    should be in the ascending order of (A,B,CP).

    (B) Implement S and CN using 8-to- 1 multiplexer.

    Thanks & best regards,
    Ramesh Raju