Hello guys!
I have to do counter mod 12 using 74192. I read some advices in other thread but i got an problem.

Starting from a fresh count...

0 0001 .. 01
0 0010 .. 02
0 0011 .. 03
0 0100 .. 04
0 0101 .. 05
0 0110 .. 06
0 0111 .. 07
0 1000 .. 08
0 1001 .. 09
1 0000 .. 10 .. Note 1
1 0001 .. 11
1 0010 .. 12
1 0011 .. 13 .. Note 2

Note 1: A BCD counter will reset on 10, and sent a carry signal to the next stage. Look for this on the datasheet.


Note 2: A simple 3 input AND gate can sense the number thirteen, this is used to send a reset signal to the most significant digit (the simple flip flop) and a preset signal to the 74192, taking it back to the number 1. I have highlighted the digits used in the reset signal in red.

0 0001 .. 01
0 0010 .. 02
0 0011 .. 03
0 0100 .. 04
0 0101 .. 05
0 0110 .. 06
0 0111 .. 07
0 1000 .. 08
0 1001 .. 09
1 0000 .. 10 .. Note 1
0 0001 .. 01
0 0010 .. 02
0 0011 .. 03 ..

Carry is on H only a short moment.
Can anybody help me?

 

Holo borecky

Help You about what ??

If you're planning a MOD 12 counter you would need two 74LS192 chips connected in cascade.
And really the carry is L only for a short period of time if we are talking about the 74LS192.

 

Instead of using a BCD counter, why not use a binary counter (it will count up to 15).

 

You say that you HAVE to do a mod 12 counter using a 74192. Why? Is it simply a requirement of the assignment? What other components are you allowed to use?

 

Maybe there is a mistake in the assignment. Perhaps the assignment is to use a 74193 to make a mod-12 counter.

 

That's what I'm hoping. But, it's possible that they get to use two '192 counters and the point is to work with multi-digit BCD modulo counters. Hopefully the OP will clarify.