That might be doable with a solenoid.If by stroke length you mean the length the razor cuts to its ending position (before retracting back up), then it is 1 inch.
Do you know what force is required?
That might be doable with a solenoid.If by stroke length you mean the length the razor cuts to its ending position (before retracting back up), then it is 1 inch.
No I do not. It is a cigar cutter. I think as long as it is not cutting slow, it will not require much force.That might be doable with a solenoid.
Do you know what force is required?
The motor turns 180 then stops briefly and either reverses 180 or continues 180. This
is going to require another timer.
With a hobby servo, you command it to move to a position. There is no need for a timer. Implied is that a servo does not spinIs the motor geared to 30 RPM? If not, how do you expect it to rotate only 180° in 1 second. An ungeared motor will spin at 1000s of RPMs. In one second it will spin many times around.
Ok. You mention a servo. RPM is not relevant when talking about servos.The motor I am looking at is geared it rotates at 200 rpm
A continuous servo either spins in either direction or stops. Pulse width less than or greater than 1500 mS turns in either direction. A pulse width of 1500 mS stops.A continuous rotating servo might work better
A servo can easily be positioned accurately at any number of degrees, from 0 to 180.Pretty accurate. The motor is fixed to a cam which drives a down a blade. Like a cam and follower system. It is a cutting mechanism. The motor is driving the cutting motion.
Good point.By far, the easiest thing to do is use a switch that is activated by the cam just after the cut is finished and the blade is retracted. That switch would then stop the motor. The push button overrides the switch to start the motor going again, getting it past the other switch to perform the next cut.
Probably a normally closed reed switch that is connected in series to the battery would work. When the cam finishes a 180 degree turn it pushes against it. I like your idea, but do you think it’s smarter then a solenoid?By far, the easiest thing to do is use a switch that is activated by the cam just after the cut is finished and the blade is retracted. That switch would then stop the motor. The push button overrides the switch to start the motor going again, getting it past the other switch to perform the next cut.
Probably a normally closed reed switch that is connected in series to the battery would work. When the cam finishes a 180 degree turn it pushes against it. I like your idea, but do you think it’s smarter then a solenoid?
Not sure the solenoid will work. It needs to fit in a tight space (as shown in the photo) and will need 1” stroke which not many small solenoids offer.That might be doable with a solenoid.
Do you know what force is required?
That will be to slow. It needs to be fast to cut the cigar.If you want to stay with the DC motor use a 30rpm motor which provides 1/2 rotation in 1 second.
It moves 180 degrees in 1 second. That's what you said was needed in post #40 correct?That will be to slow. It needs to be fast to cut the cigar.
It doesn’t have to be one second. It can be .25 seconds or any amount of time that will cut the cigar fast and move only 180 degrees.It moves 180 degrees in 1 second. That's what you said was needed in post #40 correct?
Any quick press button. Doesn’t matter if it’s momentary or not, as long as it does the job with one quick pushGetting more complicated using a single switch. Do you mean a quick press of the button or press and hold as in the circuit posted?
Understood. These concepts are new to me, so I will wait on that circuit schematic. I only have 2N2222 transistors and IRF 540 Mosfets, so it would be convenient if you could use one of those.I’m on the road, so I can’t draw a schematic but…
A solution is to replace the buttons with PNP or P-channel transistors. You’ll need to separate the buttons and pin 7 positive source. Add the resistor value from the positive connection to each of the resistors individual resistor to get the resistor value for the pushbutton.
Then, I’d drive/ connect the base/ gate of each transistor (button) to a flip-flop.
A flip-flop has two outputs: Q & Q-bar. These are complimentary. When either is high, the otheris low. These outputs and the transistor buttons will cause you servo to move back and forth.
by Aaron Carman
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by Aaron Carman