- Joined Dec 24, 2009
Are you looking to get to some specific voltage with the output? As mentioned, you can use a transistor to act as a switch. This will allow you to connect whatever voltage divider you like to the BJT output, getting the desired voltage up to your supply minus about .7V for the BJT. The 555 output pulse will only turn the BJT on, and have nothing to do with what voltage actually appears at the BJT output.How can I vary the amplitude of 1ms pulse output from 0V to 5V in steps of 0.5V without adjusting 555 supply voltage?
Normally I don't like to use the Load connect to E, almost connect to C, whatever NPN or PNP transistor, if I need to use the driver as darlington, then I will use the way as below:Does this works !!!!!
Sorry about that, for your eyes, for your brain, and for your mood.Your English translation is horrible.
Is there something wrong?The output voltage of the darlington pair of transistors depends on their hFE, their Vbe, their temperature and maybe a few other things.
Show me the circuit please, and thanks.Usually we put a transistor inside the negative feedback loop of an opamp so the flaws are cancelled.
The circuit does not produce accurate voltages. The output voltages change when the load current changes and they change when the temperature changes. The voltage even changes as the output transistor warms up.Pls find the modified schematic.....Is it OK ?
Can I produce the low values like 0, 0.5, 1.0 V by turning 5K ? (also 1.5, 2.0, 2.5, 3 medium values & 3.5, 4, 4.5, 5V high values at output of darlington)
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