Hello again! I was wondering if anyone was able to help explain how to calculate simple current for dual voltage delta connections? I really couldn't draw this in multisim, so please envision a Wye and Delta connections with two 10 ohm windings per phase.
Wye connected, 480v line voltage to phase = 480/1.732, or 277 volts per phase.
High voltage connections mean series impedence, then 10 Ω + 10 Ω = 20Ω. 277v / 20Ω = I =13.85A
Low voltage connections mean parallel impedences, so 277v / 5 Ω = 55.4A
Now Delta line voltage = Delta phase voltage, so does high voltage vs low voltage connections both use 480v? and the impedences are like the above series / parallel amounts above? I'm confused because of the relationship of line current =1.732 ( phase current) in delta connections.
Thanks for the help!
Wye connected, 480v line voltage to phase = 480/1.732, or 277 volts per phase.
High voltage connections mean series impedence, then 10 Ω + 10 Ω = 20Ω. 277v / 20Ω = I =13.85A
Low voltage connections mean parallel impedences, so 277v / 5 Ω = 55.4A
Now Delta line voltage = Delta phase voltage, so does high voltage vs low voltage connections both use 480v? and the impedences are like the above series / parallel amounts above? I'm confused because of the relationship of line current =1.732 ( phase current) in delta connections.
Thanks for the help!
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