Greetings everyone. Short and to the point. I understand how voltage dividers work. My project requires 3.5v to 5v. Power will be "D" batteries, advertised as 10,000 mA each. Case 1: Use (3) 1.5v in series = 4.5v and estimated 30,000 mA and we're good to go. Case 2: Use (4) 1.5v in series = 6v w/ (est) 40,000 mA and a voltage divider to bring it down to 4.5 - 5 v. HERE'S THE QUESTION: How do you figure out the LOSS of power when using a voltage divider. I'm sure there is one and that there must be an equation. Thank you in advance for your input. Regards, Fred