AHA!!For a) and d) I'm in the assumption that by "conditions of oscillation" means apply Barkhausen, that is find the frequency of oscillation for which the phase is zero or multiples of 360 degrees.
Yes but my instructor did not tell me NOT to apply Barkhausen eitherAHA!!
It appears that the instructor did not tell you to apply Barkhausen; the problem says "...determine the conditions for oscillation...".
You made the assumption that Barkhausen should apply. Perhaps your difficulty in showing the truth of that assumption should now lead you to reconsider.
In other words, look for other conditions for oscillation.
Do you know what a neon relaxation oscillator is? See:
http://en.wikipedia.org/wiki/Relaxation_oscillator
There's no feedback at all there (at least not in the ordinary sense), yet it oscillates. How could the Barkhausen criterion apply to it?
You might do some Google searches on stability in network theory, and negative resistance:
http://en.wikipedia.org/wiki/Pearson%E2%80%93Anson_effect
I already gave you my answer to that: "Perhaps your difficulty in showing the truth of that assumption should now lead you to reconsider."Yes but my instructor did not tell me NOT to apply Barkhausen either
Did you read the link to the Pearson-Anson effect? Did you see where it says " As the neon lamp exhibits negative differential resistance in the AB part of its IV curve (see the figure on the right), if it is driven by a voltage source (the charged capacitor here), it behaves as a switching element with hysteresis (a sort of Schmitt trigger)." That seems like a condition for oscillation.What does it means conditions for oscillation then?
For me, it means the frequency at which the system starts to oscillate, that is when the system is in a steady-state, as shown in the analysis above. Is there any other conditions of oscillation, apart from frequency of oscillation?
See this reference: http://en.wikipedia.org/wiki/Electronic_oscillatorWell, now that leads to the question:
Why I couldn't apply Barkhausen for this SPECIFIC circuit? Is it because (to put it simple) there is no lag/lead circuit, that is, RC circuit, in the positive feedback as in a wien bridge oscillator?