z-transform

Discussion in 'Homework Help' started by jut, Oct 10, 2009.

  1. jut

    Thread Starter Senior Member

    Aug 25, 2007
    224
    2
    I'm trying to take the (two-sided, aka defined for all n) Z-transform of

    x(n)=sin(Bn)

    What I tried to do was split x(n) into

    x(n)=sin(Bn)u(n)+sin(Bn)u(-n-1)

    But a problem arises now because the z-transform of the first equals the negative of z-transform of the second, which makes the z-transform = 0. Waaah? Could this be?
     
    Last edited: Oct 10, 2009
  2. vvkannan

    Active Member

    Aug 9, 2008
    138
    11
    I dont think the z transform would exist.The right sided sequence will converge only when magnitude of z is greater than 1 and left sided sequence will converge only when z magnitude is lesser than 1 and hence the whole series is not summable .
     
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