wyedelta

Discussion in 'Homework Help' started by albn, Jul 6, 2012.

  1. albn

    Thread Starter New Member

    Jul 6, 2012
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    what is the unbalanced current flowing in the neutral of this three-phase,four wire,208/120-volt system? A phase=52 amperes, B phase=44 amperes, C phase=46 amperes.


    A. 7.21 amperes
    B. 7.07 amperes
    C. 7.34 amperes
    D. 6.78 amperes

    Please show the computation and thanks for any help and it's highly appreciated :)al_benigno@comcast.net
     
  2. strantor

    AAC Fanatic!

    Oct 3, 2010
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    \sqrt{(Ia^{2}+Ib^{2}+Ib^{2})-(Ia*Ib)-(Ib*Ic)-(Ia*Ic)}
     
    Last edited: Jul 6, 2012
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  3. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    Why not simply

     I_n=I_a\angle{0^o}+I_b\angle{-120^o}+I_c\angle{-240^o}
     
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  4. albn

    Thread Starter New Member

    Jul 6, 2012
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    Hi! thanks for help I able to answer problems, more power to you
     
  5. mlog

    Member

    Feb 11, 2012
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    Now that makes sense.
     
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  6. strantor

    AAC Fanatic!

    Oct 3, 2010
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    Sorry I don't know the masonic symbols. Not part of the club.
     
  7. albn

    Thread Starter New Member

    Jul 6, 2012
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    Hi! guys thanks it's over the problems was solved and I really appreciate your inputs more power to you all.
     
  8. amilton542

    Active Member

    Nov 13, 2010
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    I think T_N_K's defined the negative sequence set.