A three source with a voltage of 120/208 Volts is connected to a wye load of three 10 ohms resistors and a delta connected load of three pure coils (pf=0) that draws 15 amps each. The line current to the source will be..... the correct answer is 28.6 amps. My answer comes in much higher. On the delta load I find it's line current by multiplying 15 amps by 1.732 which equals to 25.98 amps. Then on the wye connected load I find the phase current by 120 volts by 10 ohms which equals to 12 amps. Phase current equals line current in the Wye configuration. I add the line currents of the delta and wye loads.......25.98 amps + 12 amps = 37.98 amps. Help on this question will be greatly appreciated.