Why is the frequency cut-off 0.707?

Discussion in 'General Electronics Chat' started by franck_hunter, Nov 19, 2003.

  1. franck_hunter

    Thread Starter New Member

    Nov 19, 2003
    1
    0
    On the main page there is a formula which shows that the frequency cut-off (0.707) is found from 1/2*Pi*RC. But why?




    Thx in advance
     
  2. Nirvana

    Well-Known Member

    Jan 18, 2005
    58
    0
    Well If you are talking about an AC component under AC conditions then the formula for the Capacitive Reactance is:
    XC = 1/2π f C,
    Im not sure which example you are talking about, but I'll go on anyway.
    If we are going to make the Resistance (R) which is in Parallel with Capacitor C, then the formula becomes;
    XC = 1/2π f C = R, then to determine the frequency f the formula is transposed to give; f = 1/2πRC,
    Think of it like this, as XC = R the voltages across each component will be equal, plotting this out on a Phasor diagram will show that the angle of VR and VC are 45 degrees , therefore the voltage VR is equal to Vin cos(45) =Vin/(root2) which is 0.707. Basically you need to draw phasor diagrams, using complex numbers will help.

    Nirvana.

     
  3. aliashar86

    Active Member

    Nov 23, 2006
    71
    0
    plz explain

    i have never seen the formula for calculating cut-off, instead just know abt it tht it is the breakdown voltage for transistor , MOSFET . can u plz explain again tht why it is cut off at 0.7 why not more or less than tht
     
  4. Papabravo

    Expert

    Feb 24, 2006
    10,137
    1,786
    Cutoff frequency and breakdown voltage are two entirely different things. Can we backup for a moment and decide which one we are talking about.

    BTW are you aware of the following:
    Code ( (Unknown Language)):
    1.  
    2. 1 / SQRT(2) = SQRT(2) / 2 = 0.707 = sin(45) = cos(45)
    3.  
     
  5. gort

    New Member

    Dec 4, 2006
    3
    0
    me tink it was 0.7071 wen i were in school a long time ago, look it up in a sine table[ 4 fig ] to reveal the hidden angle or inverse sine on a calculator, if i remember rightly we were fiddling with rms value
     
  6. aliashar86

    Active Member

    Nov 23, 2006
    71
    0
    yes man i m aware of tht

    so wt would u sat abt cut off
     
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