Why is -EB0 drawn this way in the phasor relationship?

Discussion in 'General Electronics Chat' started by foolios, Jan 17, 2010.

  1. foolios

    Thread Starter Active Member

    Feb 4, 2009
    Phase to Phase: A phase to B phase would be the phase to neutral times square root of 3.

    I see this as a new phasor AB being ahead of the A phase.
    But I am confused in this drawing why -EB0 is drawn as a phasor the way that it is.
    Why did the author redraw the phase B to neutral this way? It's already drawn in at 120° shift. Why then draw a new one and add a negative in front of the voltage symbol?

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    Last edited: Jan 23, 2010