Why is -EB0 drawn this way in the phasor relationship?

Discussion in 'General Electronics Chat' started by foolios, Jan 17, 2010.

  1. foolios

    Thread Starter Active Member

    Feb 4, 2009
    160
    1
    Phase to Phase: A phase to B phase would be the phase to neutral times square root of 3.

    I see this as a new phasor AB being ahead of the A phase.
    But I am confused in this drawing why -EB0 is drawn as a phasor the way that it is.
    Why did the author redraw the phase B to neutral this way? It's already drawn in at 120° shift. Why then draw a new one and add a negative in front of the voltage symbol?

    ::"image removed due to hosts image bandwidth constraints"
     
    Last edited: Jan 23, 2010
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