why is calculator giving in absolute form?

Thread Starter

PG1995

Joined Apr 15, 2011
832
Hi

Please have a look on the attachment. Could you please tell me why the calculator is giving the answer (arrow points to the answer under discussion) in absolute form? (x^2 - a^2)^2 would always be a +ve number by definition, so in my opinion there was no need to use absolute form. Please help me. Thanks.

Regards
PG
 

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Georacer

Joined Nov 25, 2009
5,182
Conventional math requires that the value under a square root and its result are positive numbers.

For example:
\(\sqrt{(-5)^2}=|-5|=5\)

and in general:
\(\sqrt{x^2}=|x|\)
 
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