Where can I get shockley diodes?

Discussion in 'General Electronics Chat' started by distortedkarl, Oct 2, 2012.

  1. distortedkarl

    Thread Starter New Member

    Oct 2, 2012
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  2. t06afre

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  3. distortedkarl

    Thread Starter New Member

    Oct 2, 2012
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    I've tried looking at the DIAC's here but the lowest breakover voltage is 32V. I need something closer to 3V for breakover voltage. Do these even exist?

    I was thinking that i could make my own? Maybe get two diodes and make them into a 4 layer diode by connected one lead of each to the other?
     
  4. MrChips

    Moderator

    Oct 2, 2009
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    No. Semiconductor devices don't work like that. For the same reason you cannot make a bipolar junction transistor by connecting two diodes together.
     
  5. distortedkarl

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    Oct 2, 2012
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    Maybe I'm over thinking the whole thing. I could be wrong but I think I could use regular didoes? A normal diode needs a forward voltage of 0.7V before it can conduct right? So If i put 7 in series the series of diodes would need 4.9 volts to conduct right? Charge a capacitor from high resistance resistor that's connected to a 9 volt battery. Once the capacitor voltage goes above 4.9V the diodes would conduct and discharge the capacitor? Sorry if i'm completely wrong.

    Here is a diagram of what i'm trying to say https://docs.google.com/drawings/d/1cer4FLtmnJf97PR1RZ4e2YwltqOasCnku6yC6zysiuI/edit
     
  6. bountyhunter

    Well-Known Member

    Sep 7, 2009
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    why don't you use a Zener diode?
     
  7. Audioguru

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    Dec 20, 2007
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    A bunch of diodes in series or a zener diode simply clamps the capacitor voltage at one voltage.

    A Shockley diode (small signal ones are no longer made) breaks down and shorts the capacitor voltage to ground then opens, allowing the circuit to oscillate in a sawtooth waveform.

    Many years ago I used a PUT (programmable unijunction transistor) to do the same thing. Look at it in Google or see the datasheet for a 2N6027.
    You can also use two transistors if you want.
    Today, Digikey has more than 100,000 2N6027 PUTs in stock for $.44 each.
     
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  8. Bernard

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    Ordnary diodes donot switch, need something like tunnel diode, unijunction, programable unijunction, etc. Example: PUT 2N6028 with example ckt in thumbnail. Period is close to R*C. For a sawtooth, output is from top of cap. into a high Z .
     
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  9. distortedkarl

    Thread Starter New Member

    Oct 2, 2012
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    Thank you this is what i've been looking for. I've found a YouTube video that Explains how it works too. http://www.youtube.com/watch?v=pSFXuFs7kSA

    I wonder why they stopped making Shockley diode's?
     
  10. distortedkarl

    Thread Starter New Member

    Oct 2, 2012
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    Thank you for the circuit, this is the type of circuit i was looking for.
     
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