what is this circuit?what does it do?

 

It looks like a direct coupled amplifier - or it could be if there was an input connection.

 

It looks like something from a test paper rather than a functioning circuit.

 

transistors and resistors

 

I was tempted to add "is this for real ?"

 

Inputless multistage amplifier used in a time-wasting machine. Probably prone to oscillate madly.

 

If this is homework then the question should be :

"Find the value of V1 if VCC is 10V and get datasheets of the 2 transistors using Google."

Allen

 

Assuming the input is on the left, between the two 10k resistors, I would say this circuit is more of a power attenuator while at the same time, a voltage amplifier. Overall, i would say it is a mess.

 

what is this circuit?

It's called a "student confuser."

what does it do?

It provides an output voltage, V1, whose value you're supposed to calculate.

Other than that, it has no discernible function.

 

what is this circuit?what does it do?

An example of how to not draw a schematic??

It makes me cringe and wonder why the author didn't make any attempt to line up the resistors, use uniform spacing between transistors, and remove those unnecessary bends.

Aside from being useless...

 

Or it can be a bandgap voltage reference or a temperature measurement circit.

 

I think absf got it right. It is an exercise in calculating bias points.

 

I think absf got it right. It is an exercise in calculating bias points.

I'm surprised no one entered it into a Spice simulation yet!

 

I would, but I'm too lazy. Just eyeballing the circuit, and assuming Vcc is around 10 volts, I'm thinking Q5 and Q6 are both saturated and the output at V1 is therefore something in the vicinity of 0.10 X Vcc.

 

Maybe it's one of the circuits listed on the patent in one of the many over-unity devices ... or an "instructable".

 

I'm surprised no one entered it into a Spice simulation yet!

I'm curious does Mike going to somewhere on vacation, otherwise he might do that?

 

Dick Cappels posted my first thought (post#11). Then I ran the circuit (simulated) in my head and found it's a saturated output transistor. Now I agree with OBWO (post#9).