Hi all, let me explain what that title is on about.
My z-transform function is:
\( \frac{1}{2j} \left(\frac{z}{z-exp(jw_0T)} - \frac{z}{z-exp(-jw_0T)}\right)\) (1)
Now, the question asks for the phase, where \(w_s = \frac{2\pi}{T}\)
for \(w_s = 3w_0\)
So I make the answer to be:
\(w_0 = \frac{2\pi}{3T}\) Just by combining the two equations together and then substituting this into (1) gives:
\( \frac{1}{2j} \left(\frac{z}{z-exp(\frac{j.2\pi}{3})} - \frac{z}{z-exp(\frac{-j.2\pi}{3})}\right)\)
So \( \phi = \pm e(\frac{j.2\pi}{3})\) ?
The answer that has been provided has
\( \phi = \pm e(\frac{j.\pi}{3})\)
My z-transform function is:
\( \frac{1}{2j} \left(\frac{z}{z-exp(jw_0T)} - \frac{z}{z-exp(-jw_0T)}\right)\) (1)
Now, the question asks for the phase, where \(w_s = \frac{2\pi}{T}\)
for \(w_s = 3w_0\)
So I make the answer to be:
\(w_0 = \frac{2\pi}{3T}\) Just by combining the two equations together and then substituting this into (1) gives:
\( \frac{1}{2j} \left(\frac{z}{z-exp(\frac{j.2\pi}{3})} - \frac{z}{z-exp(\frac{-j.2\pi}{3})}\right)\)
So \( \phi = \pm e(\frac{j.2\pi}{3})\) ?
The answer that has been provided has
\( \phi = \pm e(\frac{j.\pi}{3})\)