Waveform vs. vector representaion

Discussion in 'Math' started by JosefV, Feb 5, 2010.

  1. JosefV

    Thread Starter New Member

    Feb 5, 2010
    1
    0
    Hello,

    I am doing some work with the ebook from this forum complex numbers, in the chapter "Vectors and AC waveforms" i get some missunderstanding.

    Look at the picture!

    In the third waveform where B is ahead of A, I really don't understand why the
    vector representaion from A is at -90 degrees. shouldn't it point at +90 degrees and B point at 0 degrees? If A is pointing at -90 (which is +270) degree the waveform should start in the negative direction on the phase at 1/2 pi, right ?

    [​IMG][​IMG]

    yours faithful
    Josef Vukovic

    [​IMG]
     
  2. mrmount

    Active Member

    Dec 5, 2007
    59
    7
    You yourself have said "Where B is ahead of A". So if B is at 0 degrees, and should be 90 degrees ahead of A, that means A should be -90 degrees. And just out of curiosity, if you have a question about waveform 3 you should have some doubts about waveform 2 as well. No ?
     
  3. GetDeviceInfo

    Senior Member

    Jun 7, 2009
    1,571
    230
    Several conventions are being played with in these drawings, and I can't say that it does justice to explanation.

    In the phase diagrams, time typically moves from left to right, so in the third drawing, B lags A. As the A phase is solid, it would be the reference voltage, and is typically referenced to 0 degrees.
     
  4. nsaspook

    AAC Fanatic!

    Aug 27, 2009
    2,912
    2,176
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