Calculate the volume of a sphere of the sphere, x\(^{2}\)+y\(^{2}\)+z\(^{2}\)=16 cut by the planes y=0, z=2, x=1, x=-1.
The problem I have is determining the limits of the integral. I can integrate, its just the setup that is troubling me. I know in Cartesian i would have to integrate dx dy dz. I would think the integral would be,
\(\int^{2}_{?}\)\(\int^{?}_{0}\)\(\int^{1}_{-1}dxdydz\).
I tried converting everything to spherical coordinates
x\(^{2}\)+y\(^{2}\)+z\(^{2}\)=16 \(\rightarrow\) r = 4
y=0 \(\rightarrow\) rsinθsin\(\phi\) = 0
z=2 \(\rightarrow\) rcos\(\phi\)=2
x=1\(\rightarrow\) rsinθcos\(\phi\)=1
x=2\(\rightarrow\) rsinθcos\(\phi\)=2
\(\int^{?}_{?}\)\(\int^{?}_{?}\)\(\int^{4}_{0}r^{2}sindr(d theta)(d phi)\)
But now, I'm not sure what are the limits for θ and \(\phi\)
The problem I have is determining the limits of the integral. I can integrate, its just the setup that is troubling me. I know in Cartesian i would have to integrate dx dy dz. I would think the integral would be,
\(\int^{2}_{?}\)\(\int^{?}_{0}\)\(\int^{1}_{-1}dxdydz\).
I tried converting everything to spherical coordinates
x\(^{2}\)+y\(^{2}\)+z\(^{2}\)=16 \(\rightarrow\) r = 4
y=0 \(\rightarrow\) rsinθsin\(\phi\) = 0
z=2 \(\rightarrow\) rcos\(\phi\)=2
x=1\(\rightarrow\) rsinθcos\(\phi\)=1
x=2\(\rightarrow\) rsinθcos\(\phi\)=2
\(\int^{?}_{?}\)\(\int^{?}_{?}\)\(\int^{4}_{0}r^{2}sindr(d theta)(d phi)\)
But now, I'm not sure what are the limits for θ and \(\phi\)