Discussion in 'Homework Help' started by gunes, Nov 21, 2006.

1. ### gunes Thread Starter New Member

Nov 21, 2006
8
0
Another Question,

What will be readings for the 2 voltmeters?

Regards,

2. ### Papabravo Expert

Feb 24, 2006
10,340
1,850
Hint:
The total voltage around the loop is 24 Volts
The total resistance around the loop is 18 K Ohms
Therefore the current in the loop is 1.333... mA

Apply Ohms law to each resistor and compute the voltage drop. The three voltage drops should add up to 24. So starting with +12 Volts subtract the voltage drops until you get to -12 volts.

Are you with me?

3. ### gunes Thread Starter New Member

Nov 21, 2006
8
0
It does add up to 24 volts, so my next step is subtract the voltage drops starting with +12 volts!

+12 - 2.67 = 9.33
+9.33 - 8 = 1.33
+1.33 -13.33 = -12

So what do i do next?

4. ### Papabravo Expert

Feb 24, 2006
10,340
1,850
There is no next. The readings on the two voltmeters are:

Ta Da!

9.33 VDC
1.33 VDC

What more do you want?

5. ### gunes Thread Starter New Member

Nov 21, 2006
8
0
I see, Thanks alot 4 ur help!

6. ### richbrune Senior Member

Oct 28, 2005
106
0
I got 8.733 for the top voltage meter and .9334 for the second meter, can you see what I did wrong?

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7. ### JoeJester AAC Fanatic!

Apr 26, 2005
3,403
1,227
Your IR drop on R1 is off. 2k * 1.33 mA is 2.66 V not 3.66 V

8. ### richbrune Senior Member

Oct 28, 2005
106
0
Thanks again, Rich