# Voltage division question

Discussion in 'Homework Help' started by Robert Murch, Nov 5, 2015.

1. ### Robert Murch Thread Starter New Member

Nov 2, 2015
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0
So I understand how to use voltage division if all my resistors are in series. However, I seem to be struggling understanding how to use voltage division if not all my resistors are in series. I have attached a problem, here is how I tried to solve the problem:

Vx = 4(10)/(1+2+(((1/4)+(1/4))^-1)+(((1/10)+(1/10))^-1)) = 4v

That is I want to say 4*10 divided by (4||4)+(10||10)+2+1

However, according to the answer key the answer is 2v. There must be something I am missing about how this voltage division works. I was under the impression that the general formula was: Vx = Vs(Rn/Rt). Please help.

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2. ### Jony130 AAC Fanatic!

Feb 17, 2009
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But this 4 ohm's resistors are connected in parallel so to find Vx voltage you must first find the equivalent resistance of this two resistors.
Vx = 10V * 2Ω /((4Ω||4Ω)+(10Ω||10Ω)+2Ω+1Ω) = 10V * 2Ω/(2Ω + 5Ω + 2Ω + 1Ω) = 10V * 2Ω/10Ω = 10V * 0.2 = 2V

3. ### WBahn Moderator

Mar 31, 2012
18,085
4,917
You basic problem seems to be that you want to throw memorized formulas around without understanding what they mean and what their limitations are.

It's not good enough "to be under the impression" that the general equation for a voltage divider is something. Do you understand where that equation comes from and, more importantly, what the restricts are on the circuit in order for it to be valid?

What would you do if just asked to find the current in the total circuit?

What would you do if just asked to find the current in the top 4 Ω resistor?

Knowing the current in that resistor, what would you do if asked to find the voltage across it?

4. ### Robert Murch Thread Starter New Member

Nov 2, 2015
8
0
OH right since the voltage drop for elements in parallel is equal then you have to account for both of them I see now thanks!