voltage divider

Discussion in 'Homework Help' started by alexander7, Feb 25, 2010.

  1. alexander7

    Thread Starter New Member

    Oct 11, 2009
    4
    0
    1 .The totle resistance of a series circuit is 500Ω . what percentage of the totle voltage appears across a 22Ω resistor in a series circuit?


    Please explain!

    Thanks :confused:
     
  2. jlcstrat

    Active Member

    Jun 19, 2009
    58
    3
    To find the drop, take the resistor you're looking for divided by the total. Then multiply that be the total voltage.
     
  3. shteii01

    AAC Fanatic!

    Feb 19, 2010
    3,383
    495
    I am getting 4.4% of total voltage appears across 22 Ω resistor of the voltage divider.

    Basically. V is your total voltage.
    V==100%

    Voltage across 22 Ω resistor is (22/500)V, just like jlcstrat said. Then.
    (22/500)V==x%
    You know value of V, put that value in the equation and crunch the numbers.
     
Loading...