Analysis with window not broken:
I know that the 400 Ω resistor and 200 Ω resistor are in parallel so their R_equivalent can be written as follows
R_eq = 400(200) / (400+200) = 800/6 Ω
Using the Voltage Divider formula: I get V_01 = E(R_eq/R+R_eq)
but since I have two unknowns, I don't know what to do. That 6V they inform me about plays a role but I don't know how to use it.
Substitute V_01 with 6 which would yield 6V = E(R_eq/R+R_eq)? This is also a problem I encounter while doing the second part of the problem.
Analysis with window broken:
When the window is broken, the voltage di-
vider circuit simplifies to the one shown on
the right. In this case, we have denoted the
output as vo2. Derive a relationship between
the output vo2 and the unknown variables E
and R. We note that one of the design con-
straints is that vo2 should be greater than 6 V
but less than 24 V. This yields another con-
straint equation. Write this equation in the
space below.
The resistors are connected in series so I can use the Voltage Divider formula
V_02 = E(400Ω/R+400Ω)
but then I am stuck again because E and R are not known.
Select the values for E and R to satisfy the above two constraint equations, and verify that the chosen values indeed will work. Do all your work in the space below, and backside if needed.
When the window is not broken, the voltage
divider circuit is as shown on the right. For
clarity and for comparison with the next case,
we have denoted the output as vo1. Derive a
relationship between the output vo1 and the
unknown variables E and R. We note that
one of the design constraints is that vo1 should
be less than 6 V. This yields one constraint
equation. Write this equation in the space
below.
divider circuit is as shown on the right. For
clarity and for comparison with the next case,
we have denoted the output as vo1. Derive a
relationship between the output vo1 and the
unknown variables E and R. We note that
one of the design constraints is that vo1 should
be less than 6 V. This yields one constraint
equation. Write this equation in the space
below.
I know that the 400 Ω resistor and 200 Ω resistor are in parallel so their R_equivalent can be written as follows
R_eq = 400(200) / (400+200) = 800/6 Ω
Using the Voltage Divider formula: I get V_01 = E(R_eq/R+R_eq)
but since I have two unknowns, I don't know what to do. That 6V they inform me about plays a role but I don't know how to use it.
Substitute V_01 with 6 which would yield 6V = E(R_eq/R+R_eq)? This is also a problem I encounter while doing the second part of the problem.
Analysis with window broken:
When the window is broken, the voltage di-
vider circuit simplifies to the one shown on
the right. In this case, we have denoted the
output as vo2. Derive a relationship between
the output vo2 and the unknown variables E
and R. We note that one of the design con-
straints is that vo2 should be greater than 6 V
but less than 24 V. This yields another con-
straint equation. Write this equation in the
space below.
The resistors are connected in series so I can use the Voltage Divider formula
V_02 = E(400Ω/R+400Ω)
but then I am stuck again because E and R are not known.
Select the values for E and R to satisfy the above two constraint equations, and verify that the chosen values indeed will work. Do all your work in the space below, and backside if needed.