Hello, I wanted to know If Im doing this question correctly? 1.)A voltmeter, a PF meter, and a wattmeter are connected to a balanced 3 phase, 4 wire load. The Readings are 1500 Watt, 0.50 PF, 120 Volts. What current flows? This is my understanding so far: There are 3 branches and 1 neutral branch to the transformer. If it is balanced then each branch excluding the neutral, has 500 Watts. (120Volts)(0.50PF)(3)=500Watts---------> 180=500Watts/180= I=8.33A Or I worked it out this way too.. (120Volts)(0.50PF)(SqRt3)=1500Watts 60*1.732=1500Watts 103.92=1500W/103.92=14.43A These both are two choices that are answers listed to the problem. Im having trouble understanding using the square root of 3, or multiplying with 3 for 3 phase systems. Are there any resources that will help me understand this better? I think it would be the 1st way but I'm not sure. Any help is greatly appreciated. Thank you.