Discussion in 'Homework Help' started by lisa3412, Sep 6, 2014.

1. ### lisa3412 Thread Starter Member

Sep 6, 2014
37
0
Hello. .
I have solved this.

1) -5t+10
2) 7.5
3) 41.67

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2. ### dalam Member

Aug 9, 2014
58
6
Last edited: Sep 6, 2014
3. ### lisa3412 Thread Starter Member

Sep 6, 2014
37
0
I the RMS over all time of a periodic function is equal to the RMS of one period of the function.

& the RMS for a f'n over all time in the Wiki link that you provided is what I have used. Help!!

4. ### dalam Member

Aug 9, 2014
58
6
Try this :
1. Integrate the square of the function (that you got) over one period. This gives you mean square value.
2. Under root of this is RMS.

Put the limits from 0 to 1 to get 58.3333

√(58.3333) =7.63

5. ### Jony130 AAC Fanatic!

Feb 17, 2009
3,991
1,116
Last edited: Sep 7, 2014