short title because can't post??
I'm just not sure how to go about solving this. I tried labeling a reference node above the resistor through which we want current. The voltage through this is \( 7V_{c}\) is it not? Which results in the current being
\(7V_{c} \times \frac{1}{R} = 7e^{\frac{-t}{2}}\)
Well this makes sense to me, at least, but when I model it in LTSpice the current decays much more quickly. I tried to reverse solve and I got a \(\tau=1.845\) but even plugging this in for 2 in my equation doesn't get the decay to happen fast enough so I'm thinking the formula/method of solving I've chosen is completely incorrect. Sorry for all the detail but I just wanted you to know I've worked on it for a while.
You can't see from the pic but \(V_{c}(0) = 10 V\) and we are solving for \(i_{x}\)
I'm just not sure how to go about solving this. I tried labeling a reference node above the resistor through which we want current. The voltage through this is \( 7V_{c}\) is it not? Which results in the current being
\(7V_{c} \times \frac{1}{R} = 7e^{\frac{-t}{2}}\)
Well this makes sense to me, at least, but when I model it in LTSpice the current decays much more quickly. I tried to reverse solve and I got a \(\tau=1.845\) but even plugging this in for 2 in my equation doesn't get the decay to happen fast enough so I'm thinking the formula/method of solving I've chosen is completely incorrect. Sorry for all the detail but I just wanted you to know I've worked on it for a while.
You can't see from the pic but \(V_{c}(0) = 10 V\) and we are solving for \(i_{x}\)
Attachments
-
13.3 KB Views: 14