Calculate the collector voltage Vc as Vin increases from 0-5V and hence plot the transfer characteristic Vc vs Vin (consider many points where Vc is changing rapidly). Calculate Vin when Vc = 2V. An NPN with a gain of B = 100 is used. Attempt: When Vin = 0V and 1V Vc = 0. Vin = 2V: Ib = 2 - 0.7 / 10 x 10^3 = 1.3 x 10^-4 Ic = IbB = 1.3 x 10^-4 x 1000 = 0.013 Vc = 5 - 0.013 x 1 x 10^3 = -8V I dont understand why I got a negative answer.