Urgent ! Please who can solve this ?

Discussion in 'Homework Help' started by blogs4world, Aug 19, 2014.

  1. blogs4world

    Thread Starter New Member

    Aug 19, 2014
    3
    0
    I am stuck here. Can anyone please solve this for me.
    You can do the math in a page and take snap and attach here please.
    I am attaching the circuit here
     
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  2. djsfantasi

    AAC Fanatic!

    Apr 11, 2010
    2,802
    832
    Please read this.
    Show your work so far. Then, we can see where you are "stuck". This forum is not "Homework Done For You".
     
  3. tshuck

    Well-Known Member

    Oct 18, 2012
    3,531
    675
    We are not a homework solving service.

    Please attempt YOUR homework since we've already gotten our grades and don't need more.

    We will help (read "not do it for you, but provide insight") you with your homework once you make an honest attempt at the answer and show it here.
     
  4. blogs4world

    Thread Starter New Member

    Aug 19, 2014
    3
    0
    I tried this more than 20 times. If there is only dependent voltage source then I can solve it easily but when there is dependent current source then it is tough.
    When considering 25V source then the formula comes on 1st loop...
    25-24(i1)+4(i2) = 0
    but in the 2nd loop there is one current source how to apply there KVL ?
    -4(i2)+4(i1)-0.1(vx) = 0 ??? since 0.1vx is a current, how to count it as a volt?

    But when I am considering 5A is active
    then 1st loop should be ??

    Really it is heck to me. Can anyone help me please?
    I took help of B.L thereza book but there is no such an example and no KCL OR KVL applied but a critical formula applied. if you can help me to understand then i will be grateful to you
     
  5. blogs4world

    Thread Starter New Member

    Aug 19, 2014
    3
    0
    I did it in my notebook but stuck on dependent current source. if there is voltage then i can solve but current :( :(
     
  6. MikeML

    AAC Fanatic!

    Oct 2, 2009
    5,450
    1,066
    I did this a different way:

    I just summed the current into node X.

    (25-Vx)/20 + 5 -Vx/4 + 0.1*Vx = 0

    Multiply through by 20
    25 - Vx + 100 - 5Vx + 2Vx = 0

    Solve for Vx
    125 = 4Vx

    or Vx = 31.25

    To double check:
     
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    Last edited: Aug 19, 2014
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