URGENT! Need Help on Boolean Equations please!

Discussion in 'Math' started by Chodus, Apr 2, 2008.

  1. Chodus

    Thread Starter New Member

    Apr 2, 2008
    1
    0
    Say i have an boolean equatio could anyone help me simplify it?

    Z = D'(ABC' + A'B'C + AB'C + A'BC + ABC)

    If possible could you also show your working out? thnx alot :(
     
  2. thingmaker3

    Retired Moderator

    May 16, 2005
    5,072
    6
    If this is a homework question, we could move it to the more appropriate forum. Just let us know.
     
  3. Dave

    Retired Moderator

    Nov 17, 2003
    6,960
    144
  4. MusicTech

    Active Member

    Apr 4, 2008
    144
    0
    If A/A'=0, which I am not sure of, I do not think this is correct. then the whole thing cancels out to 0.

    If not, please tell me what A/A' is...

    If it is 0, I will show you what I did, kinda senseless if it's not b/c my first step includes it...
     
  5. Mark44

    Well-Known Member

    Nov 26, 2007
    626
    1
    If '/' means division, then this doesn't make any sense, since division isn't defined for Boolean quantities:confused:. The only binary operations are AND (using juxtaposition or *, as in AB or A*B) and OR (using +).
     
  6. MusicTech

    Active Member

    Apr 4, 2008
    144
    0
    hmm didn't know that. I knew something was wrong. So much more to learn
     
  7. dhamphire

    New Member

    Aug 2, 2008
    3
    0
    here's my try tough i'm nt so sure about it.
    Z = D'(ABC' + A'B'C + AB'C + A'BC + ABC)
    Z= ABC'D' + A'B'CD' + AB'CD' + A'BCD' + ABCD'
    Z= ABD'(C'+C)+B'CD'(A+A')+A'BCD'
    Z=ABD'+B'CD'+A'BCD'
    Z=ABD'+CD'(B'+A'B)
    Z=ABD'+CD'(B'A')
    Z=ABD'+CD'B'A'
    Z=D'(AB+A'B'C)
    Z=D'(ABC)
    z=ABCD'
     
  8. Ratch

    New Member

    Mar 20, 2007
    1,068
    3
    dhamphire,

    Using the logical values of 2,6,10,12,14 and the Quine-McCluskey method, I get ABD' +CD' . Look at your 5th line. B'+A'B = A' + B' , not B'A' .

    Ratch
     
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