# Unit Step Function Integral

Discussion in 'Homework Help' started by p75213, Oct 18, 2011.

1. ### p75213 Thread Starter Member

May 24, 2011
39
0
Can somebody help me with understanding how they have graphed the integral? From the integral I get the following:

10r(t)=0, t<=0
=10t, t>=0

-20r(t-2)=0, t<=2
=-20t+40, t>=2

10r(t-4)=0, t<=4
=10t-40. t>=4

I can't see how the graph has been drawn from these equations???

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2. ### Zazoo Member

Jul 27, 2011
114
43
For t<0, the ramp functions are all zero, so:
f(t)=0

For 0<t<2, only the first ramp function is non-zero, so:
f(t)=10t. (the left side of the triangle)

For 2<t<4, both the first and second ramp function are non-zero, so:
f(t) = (10t) + (-20t+40) = -10t +40. (the right side of triangle)

For t>4, all three ramp functions are non-zero, so:
f(t) = (10t) + (-20t+40) + (10t-40) = 0

p75213 likes this.
3. ### p75213 Thread Starter Member

May 24, 2011
39
0
I think I need a book that explains things a bit better. Any recommendations?