practically due to internal resistances current will flow in to 5v battery....but still i think am gonna try it....lets see how will it smell during blowing job []
I would put a resistor in serial with one of the batteries, like 10ohm 10w, or something like that.
batteries have very low internal resistance (from a few mohm to 30-50mohm, depending on the type). a 5v voltage drop over this kind of resistance will cause massive amount of current.
1.) Who knows, since it's 2 electrodes seperated by a electrolyte, maybe initially it would act like a capacitor??? Before overheating......
2) .But then again when you do dc analysis (superposition) on it you replace it with a short.
So it would be a low value resistor in parrallel with the 1 K.
if you were to parallel two batteries, the current going from the high voltaged one to the low voltaged one will just be the voltage differential / total internal resistance of the two amps.
in this case, the total internal resistance is likely in the .1ohm range, and the voltage differential is 5v. so you are talking about a 50amp current flow.