Trouble with Multiplexers

Discussion in 'Homework Help' started by Davey, Oct 17, 2005.

  1. Davey

    Thread Starter New Member

    Oct 3, 2005
    I'm working on my DSD Homework here and I'm having a little trouble with the following problem:

    I know how to for example make a 32-to-1 Multiplexer out of two 16-to-1 Multiplexers. That's easy enough, but then again that's a very clear statement. I'm having trouble understanding what is meant by "quad" 9-to-1 multiplexer or "quadruple" 2-to-1 multiplexers. Could I have just have easily said that a 32-to-1 mux could be made from a "dual" 16-to-1 mux?

    The book is very vague on the description of adding terms like "dual" "quad" etc to the beginning of fact I can't figure out the meaning at all. My only bright ideas are that they're talking about IC Chips (a quad 2-to-1 package meaning there's four 2-to-1 mux's on the IC with a common select). Either that they could be telling me to construct "four" 9-to-1 multiplexers with one 8-to-1 line mux's and four 2-to-1 line mux's. I can do that I think.

    Does anyone have any hints or explinations on where I should start? Could someone clarify what the question is asking for? I think I could solve it from there.

    Thank you,
  2. nomurphy

    AAC Fanatic!

    Aug 8, 2005
    It means for you to design four 9-1 muxes, using four 8-1's and four 2-1's.

    Should be simple enough, the output of each 8-1 is muxed with the 9th line by the 2-1's, just pay attention to the adressing.