Triggering a 555 from both edges.

Thread Starter

m121212

Joined Jul 24, 2011
96
Moderators Note: Trying to take over someone elses thread is called hijacking, and is not allowed on AAC. I have therefore given you a thread of your very own. This from How would u trigger 555 monostable on both edges?.

Sorry to revive an older thread.

There's something I don't understand about Ron's circuit suggestion with the common base for the negative edges.

I built the circuit as drawn, but when I connect the output to a 555 pin 2, the spike train vanishes. It should just be a high-impedance comparator input, no?

I tried to buffer the output with a common collector buffer, but got the same result. I will try again with a pair of common emitters (double inversion), but in the meantime maybe someone knows what's happening?
 
Last edited by a moderator:

tindel

Joined Sep 16, 2012
936
That's a great circuit from Ron... Good thinking!

As far as your circuit... if you're driving a high input impedance, 100k output impedance is probably too high try lowering the pull up resistor value
 

Thread Starter

m121212

Joined Jul 24, 2011
96
Yes, I played around with decreasing that resistor from 100k to 8.2k and to 1k, but without success.

Building the circuit, with the solitary exception that I am using a 5v supply instead of a 10v, I get the screenshot shown at the output of Ron's circuit.

When I load it with the 555 trigger pin (should be a high-impedance comparator input) I get the second screenshot. The falling edge detection (common base bjt) seems to have some trouble.

Simulation shows the same behavior (instead of 555 pin I used an LM111 comparator).
 

Attachments

tindel

Joined Sep 16, 2012
936
Can you provide us with a circuit diagram? It's hard to troubleshoot something that you don't know what it is!

If it is driving a capacitive load... It may be taking too much time to charge discharge the capacitor
 

Thread Starter

m121212

Joined Jul 24, 2011
96
Sure, see attached.

Vin is a square wave from 5v to 0v, 10khz.

Circuit is the same as Ron's except for the 8.2k pull-down.
 

Attachments

Thread Starter

m121212

Joined Jul 24, 2011
96
It's the spike equivalent of a pulse train :) Perhaps not exactly common parlance, but perhaps now it's clearer.

As a sanity check, I re-ran using an actual 555 model instead of the comparator. It's slightly better, but something is still going on with that falling edge.

The 555 is configured as a monostable pulse generator , to output ~25uS wide pulses when the trigger is fired.

As you can see here, the falling edge can't quite pull the trigger. Emotionally weak I guess!
 

Attachments

crutschow

Joined Mar 14, 2008
34,462
Try increasing the value of C1 and reducing the value of R2. Note that all the current to pull the output low has to come from C1 and R2 through T1 since T1 is common-base.

The simplest circuit is probably a CD4077 XNOR (not XOR) gate with a resistor and capacitor as shown in Post #11 by Ron H.
 
Last edited:

Thread Starter

m121212

Joined Jul 24, 2011
96
You're absolutely correct. That made all the difference. Thank you! And Ron, thanks for teaching us the clever trick.
 
Top