Transistor Differential Pair analysis

Discussion in 'Homework Help' started by eng kryptonite, Feb 13, 2010.

  1. eng kryptonite

    Thread Starter New Member

    Jan 25, 2010
    17
    0
    Parameters: VTn = 0.75 V, Kn = 2.5 mA/V2, Vdd = 10 V, Vss = - 10 V, RD = 5 kOhm, I1 = I2 = 1.9 mA. Calculate RS to make the gain (Vo/Vi) equal to 5.

    My analysis came to:

    Av = Vo/Vi = (RD1||RD2)/(Rs+RD1||RD2)

    and solving for Rs I got Rs= 2k

    It seems like its not the right answer .. any help please? :confused:
     
  2. Jony130

    AAC Fanatic!

    Feb 17, 2009
    3,957
    1,097
    What is VTn?
    And if we assume that gm=0, and RD1=RD2 then
    Av=Rd/(0.5*Rs) so Rs=2K
     
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