I'm currently trying to pass exam from transient states in electrical circuits. Problem is that when solving problems I always struggle to set the initial conditions and steady state correctly. During my studies I've learned Kirchoff Law's, Ohm's Law but none of them is of any help when determining the initial values of voltage drop on capacitor or current of inductor. They're just helpful when calculating natural response. During my studies nobody taught me when and why voltage drop occurs and how it is related to elements of circuit, and other basic stuff like this. So I'm looking for a source to get this knowledge from.
For example on what base, Uc and iL are calculated here ? :
1.
Data : E = 10, R=5, L=1, C=1
Circuit :
Solution: for t(0-) it is obvious. Both Uc and iL are 0. At t(0+) Uc = 5, iL = 1 , but which resistor causes the drop on capacitor ? One from the first or second branch ? Or both ? iL is I believe just E/2R .
2.
Data : E=10, R=5, L=1H, C=100uF
Circuit:
Solution: for t(0-) iL = 2, Uc = 10. Why here is no voltage drop ? Only resistors before point of measurement influence voltage on capacitor ?
3.
Data: L=1, C=1, E=10, R=1
Circuit:
Solution: for t(0-) Uc=0, iL = 10. Why voltage on capacitor is zero ? Shouldn't it be equal to E ?
For example on what base, Uc and iL are calculated here ? :
1.
Data : E = 10, R=5, L=1, C=1
Circuit :
Solution: for t(0-) it is obvious. Both Uc and iL are 0. At t(0+) Uc = 5, iL = 1 , but which resistor causes the drop on capacitor ? One from the first or second branch ? Or both ? iL is I believe just E/2R .
2.
Data : E=10, R=5, L=1H, C=100uF
Circuit:
Solution: for t(0-) iL = 2, Uc = 10. Why here is no voltage drop ? Only resistors before point of measurement influence voltage on capacitor ?
3.
Data: L=1, C=1, E=10, R=1
Circuit:
Solution: for t(0-) Uc=0, iL = 10. Why voltage on capacitor is zero ? Shouldn't it be equal to E ?