transfer function help

Discussion in 'Homework Help' started by jstrike21, Nov 11, 2009.

  1. jstrike21

    Thread Starter Member

    Sep 24, 2009
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    [​IMG]

    I got Vo/Vi= R/(R1+Ls+R)

    Vi is on the left and Vo is on the right


    My question is: At what frequency will the magnitude of H(jw) be maximum?
    I know at low frequencies it will be maximum but is that what i put for my answer?
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    Your transfer function is correct.

    At any frequency greater than ω=0, the output is less than that at ω=0. So ω=0 would my answer.
     
  3. jstrike21

    Thread Starter Member

    Sep 24, 2009
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    when finding corner(cut off) frequency do I take

    R/(R1+R),, which is the max value of H(jw), divided by square root of 2 and set that all equal to the transfer function?
     
  4. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    I would think the corner frequency is ω=(R+R1)/L rads/sec
     
  5. jstrike21

    Thread Starter Member

    Sep 24, 2009
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    now I have the same circuit but the is a capacitor instead of an inductor.

    Vo/Vi=R/(R1+(1/jw)+R)

    2.) What frequency will the magnitude of H(jw) be maximum?
    As frequency goes to infinity?

    3.) What is the maximum value of the magnitude H(jw)
    R/(R1+R)?
     
  6. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    Vo/Vi=\frac{R}{R1+\frac{1}{j\omega C}+R}

    2. Yes
    3. Yes
     
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