To Ambiguous on Partial ractions?

Discussion in 'Math' started by Biggsy100, Jul 13, 2014.

  1. Biggsy100

    Thread Starter Member

    Apr 7, 2014
    88
    1
    Reference attached file I am a little concerned that my Answers are a little ambiguous?

    Numerator: 6x - 7

    Denominator: (x+3)(x-2)

    = 6x- 7/x-3 (x2)

    or (2x-7)(3x-2)/x3

    I have looked at several sites online that each suggest a different 'process' to work out partial fractions; this has made it even more confusing
     
  2. Papabravo

    Expert

    Feb 24, 2006
    10,140
    1,789
    Neither one of your answers looks correct. What you are looking for is an expression that looks like"
    Code ( (Unknown Language)):
    1.  
    2. {(something_1)/(x+3)} + {(something_2)/(x-2)}
    3.  
    4. We also know that
    5.  
    6. {(Something_1)*(x-2)} + {(Something_2)*(x+3)} = 6x -7
    7.  
    As you read the online descriptions of quick ways to solve the problem they should make more sense.
     
  3. amilton542

    Active Member

    Nov 13, 2010
    494
    64
    And you can eradicate the equality sign. It's an IDENTITY. I see this all the time, even the teachers themselves can't tell the difference between an equality and an identity. With this in mind, it's actually a matter of intuition solving a problem like this.
     
  4. studiot

    AAC Fanatic!

    Nov 9, 2007
    5,005
    513
    So tell us what is the difference, perhaps using an example or two?
     
  5. amilton542

    Active Member

    Nov 13, 2010
    494
    64
    Trig' identities is a good place to start.

    cos^2 (x) + sin^2 (x) is IDENTICAL to one. The argument x can take on whatever value it likes, the IDENTITY is always true. This requirement - of course - isn't always true for an equality. An equality is restricted in what values it can take on as opposed towards an IDENTITY.
     
  6. Papabravo

    Expert

    Feb 24, 2006
    10,140
    1,789
    So Biggsy....have you figured this one out yet?
     
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