# To Ambiguous on Partial ractions?

Discussion in 'Math' started by Biggsy100, Jul 13, 2014.

1. ### Biggsy100 Thread Starter Member

Apr 7, 2014
88
1
Reference attached file I am a little concerned that my Answers are a little ambiguous?

Numerator: 6x - 7

Denominator: (x+3)(x-2)

= 6x- 7/x-3 (x2)

or (2x-7)(3x-2)/x3

I have looked at several sites online that each suggest a different 'process' to work out partial fractions; this has made it even more confusing

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2. ### Papabravo Expert

Feb 24, 2006
10,340
1,850
Neither one of your answers looks correct. What you are looking for is an expression that looks like"
Code ( (Unknown Language)):
1.
2. {(something_1)/(x+3)} + {(something_2)/(x-2)}
3.
4. We also know that
5.
6. {(Something_1)*(x-2)} + {(Something_2)*(x+3)} = 6x -7
7.
As you read the online descriptions of quick ways to solve the problem they should make more sense.

3. ### amilton542 Active Member

Nov 13, 2010
494
64
And you can eradicate the equality sign. It's an IDENTITY. I see this all the time, even the teachers themselves can't tell the difference between an equality and an identity. With this in mind, it's actually a matter of intuition solving a problem like this.

4. ### studiot AAC Fanatic!

Nov 9, 2007
5,005
515
So tell us what is the difference, perhaps using an example or two?

5. ### amilton542 Active Member

Nov 13, 2010
494
64
Trig' identities is a good place to start.

cos^2 (x) + sin^2 (x) is IDENTICAL to one. The argument x can take on whatever value it likes, the IDENTITY is always true. This requirement - of course - isn't always true for an equality. An equality is restricted in what values it can take on as opposed towards an IDENTITY.

6. ### Papabravo Expert

Feb 24, 2006
10,340
1,850
So Biggsy....have you figured this one out yet?