Time constant, coil collapse

Discussion in 'General Electronics Chat' started by vandaycalta, Apr 1, 2016.

  1. vandaycalta

    Thread Starter Member

    Mar 22, 2016
    53
    4
    Hello all!
    I was thinking earlier about a npn darlington switching the primary side of a coil and wondered about the following:

    If you have a coil with voltage of 10v, resistance of 10 ohms and current of 1 amp that is switched using a npn darlington transistor and you charge the coil for the 5 time constants to fully reach the 1 amp, will it take 5 time constants for the current to reach zero using a npn darlington? I assume if you were to use breaker points there would be more resistance but with a transistor darlington I would thing that there would be no additional resistance and it would take the same 5 time constants to reach 0 amps.

    Am I kinda on the right track here?

    Val
     
  2. mcasale

    Member

    Jul 18, 2011
    210
    12
    What do you mean by "breaker points"?

    Charging the coil will take 5 time constants (L/R), but the Darlington will also have a voltage drop, so you won't reach 1 amp.

    Discharging the coil is the same deal, except I don't understand how you want to do it. Be sure you protect your transistor with a flyback diode.

    Switching is better done with a MOSFET --- lower drain-source voltage when it's on.
     
  3. wayneh

    Expert

    Sep 9, 2010
    12,127
    3,048
    Why would the breaker points offer more resistance? I would think that would be the low-resistance solution. They worked great for a long time before electronic ignitions came along. A MOSFET might be superior but as noted, you have to protect it.
     
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