Hey Allen.... I do want to play with MrChips suggestion while I also reference your simulation schematic. To get the end size of the circuit as small as possible though, I want to use either a 4060 or a 3909 as a clock instead of the AMV I used previously.Did you try MrChips' circuit using 74HC164? I simulated the circuit using proteus and it worked fine. See the sim attached.
But you cannot connect 6V directly to the 74HC164. You can pass the 6V through a diode (1N4001) to drop 0.6V before feeding the Vcc of the 74HC164.
Since you're also using the proteus sim, you might try it out yourself.
Allen
I breadboarded the 74164 circuit and found that it was working fine. Instead of using the astable multi-vibrator circuit I am using a 555. If you're using 6V for Vcc it might be too high and can spoil the 74HC164 in long run. Just put a 1n4001 or 1n4148 in series with the 6V battery on the positive terminal before entering your circuit.ImWolf said:Hi Allen,
I recreated your sim schematic and it kinda works in Proteus.... (the led's all come on in sequence and stay lit, then they all go off in sequence.) A cool effect but not the same as what I had built previously.
When I build the exact same circuit on a bread board though, it does nothing at all....
Any ideas?
Thanks,
Wolf
Yes, you're right. It should be able to work from 2 to 6V on Vcc. I thought that 74HC was the same as 74LS... sorry.the 74HC164 is rated at 7V max. input, so really not sure why 6V would be an issue.
Hey Allen..... You're the only one here trying to help me with this different version of the same circuit I already did, so you need not apologize for anything.... I really appreciate the time you're giving me.Can you describe the problem or show us a picture of the problem?
Yes, you're right. It should be able to work from 2 to 6V on Vcc. I thought that 74HC was the same as 74LS... sorry.
Allen
OK..... ("be careful what you ask for") :b1) When a schematic is drawn it is acceptable to have multiple icons of power and ground. In the real circuit these are not multiple power supplies. All the power connections represent a single node. All the ground connections are a second single node.
Hey Chips..... thanx for returning to this thread.... I still need some help making a smaller version of the first attempt. (it will barely fit in my model if I chop some corners, but I'd rather use your earlier suggestion and make a circuit with less components and less voltage.)
Yes, I've seen plenty of schematics where there are multiple positive and negative connections, and of course IC's shown with pins completely out of place.... but at my skill level I prefer to keep things as visually realistic as possible. I think this helped me while I was soldering up my first board because by the time I flipped it over and was dealing with all that "blind soldering", I pretty much had the circuit memorized by then.
2) Do not connect capacitors directly to output signals. This is asking for trouble. You will see increased current spikes when the output driver attempts to overcome the capacitance of the load.
I've read this particular point of yours more than the rest and I still don't understand what you're describing bud... maybe you can express this lesson in other terms? I never did use a capacitor like this on my BB because it didn't seem to do a thing in the software. It's my understanding though that it should have because a capacitor is supposed to "stall" the current flow?
3) What you have not shown are power supply filter capacitors. This is very important and not optional. Put a 0.1μF capacitor between the Vcc and GND pins of the 74HC164. Put a 10μF electrolytic capacitor across the power supply lines where the battery power enters the board.
Chips, if I create a connection of any sort (with a capacitor, diode, anything in the path) between the + and - of the IC, won't that short the whole thing out?
The lowest C I have on hand are 4.7. I never used (or was it suggested) a filter C on my 9V board of this circuit and I ran that thing for 3 days straight without any problems.
I do have a variety of capacitors, but I don't know if they are electrolytic, ceramic, psychotic, or what..... they are polarized though.... :b
4) It is best to show a photograph of your board, not a "virutual BB". This way we can catch real mistakes, not virtual mistakes.
I do have a few 555's, but I was playing around with a 3909 instead.... (didn't behave the same as the AMV though for clocking the other IC).555 timers do not eat battery power quickly if you choose CMOS 555 such as TLC555 or LMC555.
I think I actually understand what you're saying here Chips, but since you didn't use terms I expect, I need to ask you some Q's....Diodes can be used to drop voltages. Each diode will drop about .6 to .7 volts.
The voltage drop across a resistor is directly related to the current through the resistor.
Hence the diode is a better choice for reducing the 6V supply.
The LM3909 is meant to be an LED flasher, not as a clock circuit which your circuit requires.I do have a few 555's, but I was playing around with a 3909 instead.... (didn't behave the same as the AMV though for clocking the other IC).
My 555's are stamped NE555P / XSD 218G
(When you're first starting out playing with electronics and go to eBay to buy a bunch of cheap stuff, hard to say what you've really got on hand) :b
No. A resistor has almost constant resistance and hence obeys Ohm's Law, I = V/R. The voltage drop across the resistor will vary with the current, V = IR.I think I actually understand what you're saying here Chips, but since you didn't use terms I expect, I need to ask you some Q's....
A) Is a diode just like a resistor, but used for smaller increment drops of current/voltage passing on to the next component?
For an LED, we want to control the current, not the voltage. That is why we use a resistor. A perfect constant current source has infinite resistance. Hence for an LED circuit, the higher the resistance, the better it is as a constant current source presuming that we have satisfied the LED current requirements.B) If a diode is a better choice for dropping the voltage entering an IC, why isn't a better choice to restrict voltage to the anode of an LED?
You would be best to use a constant voltage circuit such as a 3-terminal voltage regulator or a zener diode circuit.C) If you're building a circuit and you must have a certain IC that max's out at 5V, but you also need 9V to power a must have LED strip, would you use ohm's law and use a series of diodes, or would you use a single resistor to restrict current to the IC?
I am only responding to the drawbacks of using a resistor to lower the supply voltage. Are you certain that your supply voltage does not exceed 6V? Putting a 1N4001-1N4007 series diode in series with the 6V supply followed by a 10μF electrolytic cap to ground seems like a good idea.D) Since I'm building a circuit with an IC that's rated at 7V max, and I'm using a 6V supply, why do I want to restrict the voltage at all?
Hey Chips..... thanx for returning to this thread.... I still need some help making a smaller version of the first attempt. (it will barely fit in my model if I chop some corners, but I'd rather use your earlier suggestion and make a circuit with less components and less voltage.)1) When a schematic is drawn it is acceptable to have multiple icons of power and ground. In the real circuit these are not multiple power supplies. All the power connections represent a single node. All the ground connections are a second single node.
I've read this particular point of yours more than the rest and I still don't understand what you're describing bud... maybe you can express this lesson in other terms? I never did use a capacitor like this on my BB because it didn't seem to do a thing in the software. It's my understanding though that it should have because a capacitor is supposed to "stall" the current flow?2) Do not connect capacitors directly to output signals. This is asking for trouble. You will see increased current spikes when the output driver attempts to overcome the capacitance of the load.
Chips, if I create a connection of any sort (with a capacitor, diode, anything in the path) between the + and - of the IC, won't that short the whole thing out?3) What you have not shown are power supply filter capacitors. This is very important and not optional. Put a 0.1μF capacitor between the Vcc and GND pins of the 74HC164. Put a 10μF electrolytic capacitor across the power supply lines where the battery power enters the board.
OK..... ("be careful what you ask for") :b4) It is best to show a photograph of your board, not a "virutual BB". This way we can catch real mistakes, not virtual mistakes.
Allen..... I'm still struggling to make this 164 do anything it's advertised as being capable of.... sorry I wasted so much time with it!I breadboarded the 74164 circuit and found that it was working fine. Instead of using the astable multi-vibrator circuit I am using a 555. If you're using 6V for Vcc it might be too high and can spoil the 74HC164 in long run. Just put a 1n4001 or 1n4148 in series with the 6V battery on the positive terminal before entering your circuit.
I'll post my breadboard when my photo is ready.
Allen