I think your circuit is incorrectly drawn.Ok attached.
Perhaps you didn't read the notes on my diagram in the preceding post. I thought they explained the function of the diode. Sorry if they aren't all that legible - the thing was done rather hastily. The notes explain that the diode conducts when the SCR current has fully commutated - the reverse (turn-off) current coming from the charged series inductor-capacitor combination commutates from the SCR to the diode. The diode then conducts until the turn-off current pulse falls to zero - at which stage both the SCR {+ LOAD} and the diode are off.Ok. My question is why is there a diode across the thyristor?
This is presumably your homework so you should contribute as well ....Ok. Well probably I don't understand how it fully operates. Can you explain to me more what happens when the switch is closed?
There are many classes of forced commutation - the circuit I gave is only one simple option.Look is it possible to explain to me please, this is not homework, I'm studying for an exam and don't understand. The notes say a lot but I can't figure it out.
It says that closing the switch forces the anode of the thyristor to negative, charge is removed from the SCR and after a time Toff it can block forward voltage again.
Can you explain all that in a different manner??
by Aaron Carman
by Jake Hertz