Hey guys, here are some questions regarding Thevenin's Theorem
For this question. it is stated that no load resistance is connected, not really sure what does this mean though. I'm supposed to find Vth for this question.
Vs = 6v, Is = 2mA, R1 = 2 kΩ, R2 = 4 kΩ, R3 = 6 kΩ
First, I break the network at the 6k load.
Ok so for this question, I started with the mesh equations with the top left mesh being I1 in the clockwise direction and I2 the bottom mesh also going in a clockwise direction.
-6 + 4K(I1) +2k( I1-I2) = 0 and I obtained I1 = 5/3 mA
I2 = 2 x 10^-3
Using KVL, Voc is 4k(I1) + 2k(I2)
= 4k(5/3 x 10^-3) + 2k(2 x 10^-3)
= 32/3 V
= Vth
Rth = (2k//4k) + 2k = 10/3 kΩ
Would this be correct?
For this question. it is stated that no load resistance is connected, not really sure what does this mean though. I'm required to find the Rth for this question.
R1 = 9.5 kΩ: R2 = 8.0 kΩ
VS1 = 3 V : VS2 = 3 V : IS = 50 mA
This one I honestly have no idea at all so I hope you guys can help me.
Thanks in advanced, sorry if its too lengthy..
For this question. it is stated that no load resistance is connected, not really sure what does this mean though. I'm supposed to find Vth for this question.
Vs = 6v, Is = 2mA, R1 = 2 kΩ, R2 = 4 kΩ, R3 = 6 kΩ
First, I break the network at the 6k load.
Ok so for this question, I started with the mesh equations with the top left mesh being I1 in the clockwise direction and I2 the bottom mesh also going in a clockwise direction.
-6 + 4K(I1) +2k( I1-I2) = 0 and I obtained I1 = 5/3 mA
I2 = 2 x 10^-3
Using KVL, Voc is 4k(I1) + 2k(I2)
= 4k(5/3 x 10^-3) + 2k(2 x 10^-3)
= 32/3 V
= Vth
Rth = (2k//4k) + 2k = 10/3 kΩ
Would this be correct?
For this question. it is stated that no load resistance is connected, not really sure what does this mean though. I'm required to find the Rth for this question.
R1 = 9.5 kΩ: R2 = 8.0 kΩ
VS1 = 3 V : VS2 = 3 V : IS = 50 mA
This one I honestly have no idea at all so I hope you guys can help me.
Thanks in advanced, sorry if its too lengthy..