Just a quick question on starting this problem, is it ok to use mesh current on just the 1st two loops and solve for Ib, then substitute that into the dependent current source to find that current?
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Yes, you can solve the lefthand side and then take that results and use it to solve the righthand side. That is because there are no elements in the two lefthand loops that are dependent on the results on the righthand circuitry.Just a quick question on starting this problem, is it ok to use mesh current on just the 1st two loops and solve for Ib, then substitute that into the dependent current source to find that current?