Thevenin equivalent and calculating I

Discussion in 'Homework Help' started by uraza, May 24, 2014.

  1. uraza

    Thread Starter New Member

    May 24, 2014
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    I am studying for an exam and in this old exam: http://www.eit.lth.se/fileadmin/eit/courses/etia01/1213/maj12.pdf

    Question 2c. Assume that the points p and p' are connected and the same for q and q'. What is the current I?

    To me the answer should be I = V_th/R_th. Where V_th is the Thevenin equivalent voltage for the left circuit and same for R_th. This should then be I = 1.5V/15.

    However, according to the answer it is I = 1.5V/(15+15).

    Could anyone help me explain why this is?
     
  2. Jony130

    AAC Fanatic!

    Feb 17, 2009
    3,957
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    This diagram explains everything
     
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  3. uraza

    Thread Starter New Member

    May 24, 2014
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    Thank you! I got it now since they're in series. Didn't think I needed to look at the right circuit's resistance.
     
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