Thevenin Circuit

Discussion in 'Homework Help' started by Circuitboy, Aug 27, 2006.

  1. Circuitboy

    Thread Starter New Member

    Aug 27, 2006
    3
    0
    Hoping someone can help.....This has to do with a simple THEVENIN CIRCUIT with only 3 components.(1) AN AC SOURCE VOLTAGE AT 40 VOLTS ZERO DEGREES (2) AN INDUCTOR XL=30 (3)A RESISTOR 10 OHMS

    All three are connected end to end in series....WHAT I WANT TO FIND OUT IS THE THEVENIN VOLTAGE and the THEVENIN IMPEDANCE

    CAN YOU GIVE ME THE ANSWER IN BOTH POLAR AND RECTANGULAR FORM AND HOW YOU DO THE CALCULATIONS

    *THE LOAD OF THE CIRCUIT WOULD COME FROM ACROSS THE RESISTOR*
     
  2. hgmjr

    Moderator

    Jan 28, 2005
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  3. beenthere

    Retired Moderator

    Apr 20, 2004
    15,815
    282
    We have deleted your latest post, as it duplicated this one.

    If you can indicate what satge of your calculations are causing problems, someone can probably help you to see the solution. But we can't help without some indication of your work.
     
  4. Circuitboy

    Thread Starter New Member

    Aug 27, 2006
    3
    0
    To find the thevenin voltage you have to remove the load so that it becomes open circuit, but when I remove any load it's still a closed loop; or is it that you have to remove the load resistor rather than an actual load...I am confused......I SENT THE SECOND QUEST BECAUSE THERE WAS AN ERROR IN THE FIRST ONE..The AC source voltage is LESS THAN ZERO DEGREES AND NOT JUST ZERO DEGREES AS WAS STATED IN MY FIRST THREAD.
     
  5. beenthere

    Retired Moderator

    Apr 20, 2004
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    Hi,

    Maybe I need to learn something. I always thought the AC source was the standard to measure phase shift against, so it had to assume a zero value.

    If you have two elements in a series circuit, removing either one opens the current path, resulting in an open circuit.
     
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