Thevenin and norton circuits???????? pls help

Discussion in 'Homework Help' started by paulmc, Aug 1, 2006.

  1. paulmc

    Thread Starter New Member

    Aug 1, 2006
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    could someone please solve this problem for me,i don't know where to start, any help would be great. thank you
     
  2. Papabravo

    Expert

    Feb 24, 2006
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    I wouldn't open a word document posted on a forum if my life depended on it. Sorry.
     
  3. circuithead

    New Member

    Aug 1, 2006
    5
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    Maybe it would be easier for someone to help you if you uploaded the image and posted the link. Good luck, I'm struggling on Thevenin a bit myself.
     
  4. hgmjr

    Moderator

    Jan 28, 2005
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    I converted paulmc's word document to PDF.

    hgmjr
     
  5. Papabravo

    Expert

    Feb 24, 2006
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    The voltage source equivalent of 4A across 3 ohms is 12 Volts in series with 3 ohms. Now we can add 12 Volts plus 5 Volts to get 17 volts, and we can add 8 ohms and 3 ohms to get 11 ohms. So the Thevenin equivalent for Q6A is:

    17 Volts in series with 11 ohms.

    For Q6B the norton equivalent is 1.54... Amps across 11 Ohms
     
  6. hgmjr

    Moderator

    Jan 28, 2005
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