# the maximum symmetrical swing in output voltage

Discussion in 'Homework Help' started by ADCapacitor, Apr 24, 2016.

Feb 3, 2016
42
0
Hello
I don't quite understand what does the question mean
So I ask my teacher and he tells me draw the load line first
I try to write down the dc and ac load line equation.
dc:
Id=-Vds/(Rd+Rs) + Vdd/(Rd+Rs)
Id=-Vds/5000 +12/5000
ac:
Vds=Vd-Vs
Vds=-id*(Rd//RL)-id*Rs
id=-Vds/3500

I put Vds=0 and Id=0 to dc load line equation
then I get the x-intercept and y-intercept
But I put Vds=0 and Id=0 to ac load line equation
I get both 0 at LHS and RHS
How to find the x and y intercept and plot the ac load line?

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2. ### WBahn Moderator

Mar 31, 2012
18,085
4,917
The question is simply asking how large the amplitude of the output signal can be, about the quiescent point, without clipping.

Feb 3, 2016
42
0
Do you mean the amplitude of Vds?

4. ### WBahn Moderator

Mar 31, 2012
18,085
4,917
No. Vds is not the output of the amplifier -- Vout is (so Vout relative to ground).