# test

Discussion in 'Off-Topic' started by PRS, Mar 15, 2010.

1. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
$$frac{a + b}{c}$$

Why doesn't this work, anyone?

2. ### t_n_k AAC Fanatic!

Mar 6, 2009
5,448
782
Try this .....

insert \frac{a+b}{c}

between the "$" delimiters - you need the "/" in front of the second "tex" inside the terminating square brackets.

And you then get what you wanted ...

" alt="" delimiters - you need the "/" in front of the second "tex" inside the terminating square brackets.

And you then get what you wanted ...

$\frac{a+b}{c}$" />

3. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
$\frac{a + b}{c}\$

Thank you, very much!

Last edited: Mar 15, 2010
4. ### Wendy Moderator

Mar 24, 2008
20,766
2,536
$\frac{a + b}{c}$

Hope it helps. Note the slash is backwards.

Something I've found odd doing this for the book, the finished product is actually an illustration. You can copy and paste it as such.

• ###### temp.GIF
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Last edited: Mar 15, 2010
5. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
And I thank you, too, Bill. Little things were throwing me off. Now I think I'm ready to learn this thing. Is it okay if I practice on this board or is there another place reserved for practice?

Mar 24, 2008
20,766
2,536

Aug 24, 2008
989
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Thanks.(nt)

8. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
This should be V1 with 1 subscripted:

$V_1$

$V_out$

Nope, trying again...

$V_{out}$

That woiked!

Now howabout a superscript such as 2^2 = 4?

$2^2 = 4$

Excellent. What about 2^10 = 1024?

$2^10 = 1024$

Nope, we need brackets...

$2^{10} = 1024$

Ok, the point about more than two digits in an operand needing brackets is well taken. Here's tp printing sqrt{144} = 12 and getting it right the first time!

$sqrt{144} = 12$

Yahoo! I'm on my way! Now for something a little more complicated. But we'll do that tomorrow.

Last edited: Mar 16, 2010

Mar 24, 2008
20,766
2,536
10. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
Awesome, Bill! Thanks! As soon as I get some ink for my printer I'll copy these lists and keep them next to my computer. Gotta mow a few lawns first.

11. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
Okay, I just ran into a problem. I tried to write the formula for an RC filter, which is 1/(2*pi*R*C) in the form you would find it in a book and I did this (without the TEX parameters:

\frac{1}{2piRC}\

which gives this:

$\frac{1}{2piRC}\$

But I would rather have a nice looking pi. So.... I read up on it and it seems \pi will do the trick....

Without tex I wrote: \frac{1}{2\piRC}\ the \pi supposedly creating an actual Greek pi....

$\frac{1}{2\piRC}\$

That didn't work. Anyone out there got a suggestion?

Let's try this: \frac{1}{2\{pi}RC}\

$\frac{1}{2\{pi}RC}\$

Nope.

Last edited: Mar 17, 2010

Apr 5, 2008
15,649
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13. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
Last edited: Mar 17, 2010
14. ### Wendy Moderator

Mar 24, 2008
20,766
2,536
$\frac{1}{2\pi RC}\$

You have brackets separating your \ and pi.

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15. ### retched AAC Fanatic!

Dec 5, 2009
5,201
312
You need a space after the /pi and the RC
$\frac{1}{2\pi RC}\$

Code ( (Unknown Language)):
1. that is  \frac{1}{2\pi RC}\
2.                       ^ notice the space

16. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
Thanks. Now I can get on with my lessons.

17. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
Thanks again, Bill. If there are fine cryptic points, I'll be sure to find them!

18. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
Here is the equation for an RC filter.

$f = \frac{1}{2\pi RC}\$

19. ### PRS Thread Starter Well-Known Member

Aug 24, 2008
989
35
Well, that worked. So let's try other symbols:

$V(t) = cos(\omega t + \phi)$

I forgot the constant Vmax......

$V(t) = V_{max}cos(\omega t + \phi)$

What about sigma used for integration?

$\sigma$

That's the small one. Here's the big one from the symbol menu...

This is big Ʃ

Last edited: Mar 18, 2010
20. ### retched AAC Fanatic!

Dec 5, 2009
5,201
312
I think Paul has a problem....He keeps talking to himself!