T-equivalent

Discussion in 'Homework Help' started by mo2015mo, May 16, 2013.

  1. mo2015mo

    Thread Starter Member

    May 9, 2013
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    Hi guys,

    Determine whether the given solution of attached question is correct OR not ??
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    I'd say incorrect.
     
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  3. mo2015mo

    Thread Starter Member

    May 9, 2013
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    Why ? ? ? ?
     
  4. mo2015mo

    Thread Starter Member

    May 9, 2013
    157
    1
    mutual inductance is negative ??
     
  5. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    I'm not sure what you mean.

    In any event I believe the answer is incorrect - according to my worked analysis.
     
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  6. mo2015mo

    Thread Starter Member

    May 9, 2013
    157
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    how u analyse the circuit ? tell me ..
     
  7. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    It usually works the other way on the homework forum. You show your working first, then I may show you mine or (better still) offer some suggestions on how you might go about finding the solution.
     
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  8. mo2015mo

    Thread Starter Member

    May 9, 2013
    157
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    really i founded the solution under the attached question But u told me it's incorrect

    According to my information i know when the mutual inductance (M) is minus,
    added M to L1 and L2
     
  9. The Electrician

    AAC Fanatic!

    Oct 9, 2007
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    If you will show how you derived your answer then we could help you correct any errors you may have made.
     
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  10. mo2015mo

    Thread Starter Member

    May 9, 2013
    157
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    My solution method
     
  11. The Electrician

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    Oct 9, 2007
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    Consider the original circuit. If you apply a "positive" AC voltage to the V1 terminals, you get a "positive" voltage at the V2 terminals (no phase inversion, in other words).

    But, your equivalent has a shunt element of -2H. Since the voltage that appears at the open-circuited V2 terminals is just the voltage across that shunt element, you will get phase inversion due to the minus sign, so for that reason alone your equivalent is not right.

    Re-examine how you formed your equations.
     
  12. mo2015mo

    Thread Starter Member

    May 9, 2013
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    I tried to solve it as attached fig But still the same problem
     
    • fig.jpg
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  13. The Electrician

    AAC Fanatic!

    Oct 9, 2007
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    Your second equation should be -V2 = 5 s I2 - 2 s I1

    Try reversing the direction of I2 and see what equations you get, both for the original transformer and for the tee equivalent with 3H, 2H and 3H.
     
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