Is not the flux path inside the core when the primary current is at minimum and thus the flux will not radiate out to cut the secondary windings which are located outside the core?If core saturation is reached, increasing current in the primary will not result in significantly more current in the secondary.
I think this is a fair question.
But remember, Sam, the B-H curve is S shaped. So the slope is very low at the beginning (your initial question) and the end (saturation).
But I am not sure what you mean by 'how much current'. How are you proposing this is limited? Transformers are designed to have a sensibly resistance and be limited by their reactance.
If the current through the primary remains the same the flux through the core will reduce because of the low permeability of the air. Thus, the induced emf on the secondary will be reduced too.Thanks mik3
I understood that the secondary coil acts as if it were a "radar" which detects any flux intensity changes inside the core since it is wand around it as close as possible.
Now lets imagine that instead of being wand around it, we make a cut in the core such that the flux path will have to "jump" from north to south to complete its path, and place the secondary coil in that gap. Will that "produce" as much current as in the first setup?
This is changing the goalposts from the original questions which was about low current.my question "assumption" about the point of saturation is my personal effort to justify that a saturation needs to happen inside the core and when that happens then there is no more material to carry the excess flux then and only then the flux leaves the core and uses the air surrounding the core "where the secondary is" and only then will the secondary gets cut by the flux producing current in it.
I do not agree.The magnetic flux is produced by the (primary) coil, not by the core. The presence or absence of the core does not affect the total amount of flux produced, only its position in space.
by Aaron Carman
by Jake Hertz
by Don Wilcher