Hi all

I have been struggling to find the right ans for the I(R1) in this circuit.

First i consider only the voltage source by opening the current source. As such i find that I'(R1) = (4-0.7)/1K = 3.3mA

Secondly i consider the current source by shorting the voltage source. Thus i derive I''(R1) = 3mA

Finally i get I(R1) = I'(R1) + I''(R1) = 3.3m + 3m = 6.3mA

However the ans seems to indicate as only 3.3mA.

Please help to see if my reasoning is correct.

Thanks.

 

Hi wind_blast942,
After short circuiting the voltage sources for finding the current due to the current source ,you have 2 resistors 20 and 1k in parallel.
The current through the 1k resisor is going to be Is1 x (20)/(1k+20) (by current divison rule)

 

Thanks for the clarification