Superposition Theorem

Discussion in 'Homework Help' started by wind_blast942, Sep 7, 2010.

  1. wind_blast942

    Thread Starter New Member

    Sep 7, 2010
    22
    0
    Hi all

    I have been struggling to find the right ans for the I(R1) in this circuit.

    First i consider only the voltage source by opening the current source. As such i find that I'(R1) = (4-0.7)/1K = 3.3mA

    Secondly i consider the current source by shorting the voltage source. Thus i derive I''(R1) = 3mA

    Finally i get I(R1) = I'(R1) + I''(R1) = 3.3m + 3m = 6.3mA

    However the ans seems to indicate as only 3.3mA.

    Please help to see if my reasoning is correct.

    Thanks.

    [​IMG]
     
  2. vvkannan

    Active Member

    Aug 9, 2008
    138
    11
    Hi wind_blast942,
    After short circuiting the voltage sources for finding the current due to the current source ,you have 2 resistors 20 and 1k in parallel.
    The current through the 1k resisor is going to be Is1 x (20)/(1k+20) (by current divison rule)
     
  3. wind_blast942

    Thread Starter New Member

    Sep 7, 2010
    22
    0
    Thanks for the clarification :)
     
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